2y^2+32=4y

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Solution for 2y^2+32=4y equation: 



2y^2+32=4y

We move all terms to the left:

2y^2+32-(4y)=0

a = 2; b = -4; c = +32;
Δ = b2-4ac
Δ = -42-4·2·32
Δ = -240
Delta is less than zero, so there is no solution for the equation

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